HRID1622106

反应详情

EQUATION

反应方程式

HRID 1622106 的结构方程式

PROCEDURE

实验过程

Proceeding as in Reference 12, but substituting methyl 3-bromo-5-formyl-4-hydroxyphenylacetate (27.32 g, 0.10 mole) and 2-methoxyethoxymethyl chloride (0.125 mol, 14.3 mL), gave methyl 3-bromo-5-formyl-4-(2-methoxyethoxymethoxy)-phenylacetate (31.4 g (87%).