Hydrochloric Acid → H-Leu-Gly-Oet
Reaction equation
[NH:1](C(OCC1C=CC=CC=1)=O)[C@H:2]([C:7]([NH:9][CH2:10][C:11]([O:13][CH2:14][CH3:15])=[O:12])=[O:8])[CH2:3][CH:4]([CH3:6])[CH3:5].Cl>CO.[Pd]>[NH2:1][C@H:2]([C:7]([NH:9][CH2:10][C:11]([O:13][CH2:14][CH3:15])=[O:12])=[O:8])[CH2:3][CH:4]([CH3:5])[CH3:6]Participants
5
Reagents, catalysts & solvents 2
Procedure
3.12 Grams of Z-Leu-Gly-OC2H5 was dissolved in 50 ml of methanol and 8.90 ml of 1N hydrochloric acid and the solution was catalytically reduced by using palladium as the catalyst to obtain H-Leu-Gly-OC2H5.
Sources & evidence
- ORD record
- ord-6a58f1f676ab4aceb9d43b1185581192
- Source dataset
- uspto-grants-1984_10
- Patent number
- US04474754
Reaction notes
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