Potassium Iodide → HCID 14422898, compound

HRID 1639084Notes

Reaction equation

HRID 1639084 reaction equation
Cl[CH2:2][CH2:3][CH:4]([OH:15])[CH2:5][O:6][C:7]1[CH:12]=[CH:11][C:10]([O:13][CH3:14])=[CH:9][CH:8]=1.[C:16]1([N:22]2[CH2:27][CH2:26][NH:25][CH2:24][CH2:23]2)[CH:21]=[CH:20][CH:19]=[CH:18][CH:17]=1.C(=O)([O-])[O-].[Na+].[Na+].[I-].[K+]>C(O)CCC>[CH3:14][O:13][C:10]1[CH:11]=[CH:12][C:7]([O:6][CH2:5][CH:4]([OH:15])[CH2:3][CH2:2][N:25]2[CH2:26][CH2:27][N:22]([C:16]3[CH:21]=[CH:20][CH:19]=[CH:18][CH:17]=3)[CH2:23][CH2:24]2)=[CH:8][CH:9]=1

Participants

6

Reactant 4

HCID 4875Potassium IodideHCID 70961-PhenylpiperazineHCID 10340Sodium CarbonateHCID 13120353HCID 13120353, compound

Product 1

HCID 14422898HCID 14422898, compoundYield 27.1%

Reagents, catalysts & solvents 1

HCID 2631-ButanolSolvent

Procedure

This compound was prepared according to the procedure of Example 25. A mixture of 6.9 g (0.03 mole) of 4-chloro-1-(4-methoxyphenoxy)-2-butanol, 4.9 g (0.03 mole) of 1-phenylpiperazine, 16.0 g (0.15 mole) of anhydrous sodium carbonate and 0.3 g (0.002 mole) of potassium iodide in a total volume of 200 ml of 1-butanol gave an oil which solidified. The collected solid was recrystallized from 2-propanol to give 2.9 g (27%) of white crystalline powder, m.p. 103°-105° C.

Workup

  1. customThis compound was prepared
  2. customgave an oil which
  3. customThe collected solid was recrystallized from 2-propanol

Sources & evidence

ORD record
ord-cabe8b98d5184e60bcb7966a8ba97b43
Source dataset
uspto-grants-1989_11
Patent number
US04882330

Reaction notes

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