Potassium Iodide → HCID 14422890, compound

HRID 1639102Notes

Reaction equation

HRID 1639102 reaction equation
Cl[CH2:2][CH2:3][CH:4]([OH:14])[CH2:5][O:6][C:7]1[CH:12]=[CH:11][C:10]([F:13])=[CH:9][CH:8]=1.[CH3:15][O:16][C:17]1[CH:22]=[CH:21][C:20]([N:23]2[CH2:28][CH2:27][NH:26][CH2:25][CH2:24]2)=[CH:19][CH:18]=1.C(=O)([O-])[O-].[Na+].[Na+].[I-].[K+]>C(O)CCC>[F:13][C:10]1[CH:11]=[CH:12][C:7]([O:6][CH2:5][CH:4]([OH:14])[CH2:3][CH2:2][N:26]2[CH2:25][CH2:24][N:23]([C:20]3[CH:19]=[CH:18][C:17]([O:16][CH3:15])=[CH:22][CH:21]=3)[CH2:28][CH2:27]2)=[CH:8][CH:9]=1

Participants

6

Reactant 4

HCID 4875Potassium IodideHCID 10340Sodium CarbonateHCID 2697221-(4-Methoxyphenyl)piperazineHCID 14422830HCID 14422830, compound

Product 1

HCID 14422890HCID 14422890, compound

Reagents, catalysts & solvents 1

HCID 2631-ButanolSolvent

Procedure

This compound was prepared according to the procedure of Example 25. A mixture of 5.8 g (0.0267 mole) of 4-chloro-1-(4-fluorophenoxy)-2-butanol, 5.1 g (0.0267 mole) of 1-(4-methoxyphenyl)piperazine, 9.4 g (0.089 mole) of anhydrous sodium carbonate, and 0.16 g of potassium iodide in a total volume of 200 ml of 1-butanol gave a brown oil. Upon trituration with petroleum ether (30°-60° C.), the oil solidified. The collected solid was recrystallized from isopropyl ether to yield 6.4 g (64%) of white, crystalline solid, m.p. 78°-80° C.

Workup

  1. customThis compound was prepared
  2. customgave a brown oil
  3. customThe collected solid was recrystallized from isopropyl ether
  4. customto yield 6.4 g (64%) of white, crystalline solid, m.p. 78°-80° C.

Sources & evidence

ORD record
ord-de49c15584334477b708e8adbf167fa7
Source dataset
uspto-grants-1989_11
Patent number
US04882330

Reaction notes

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