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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 1639102Generated: October 31, 2026

Potassium Iodide → HCID 14422890, compound

https://huagongshe.com/reaction/1639102

Reaction equation

Participants

RoleNameHCIDCharge
ReactantPotassium IodideHCID 4875—
ReactantSodium CarbonateHCID 10340—
Reactant1-(4-Methoxyphenyl)piperazineHCID 269722—
ReactantHCID 14422830HCID 14422830—
Solvent1-ButanolHCID 263—
ProductHCID 14422890HCID 14422890—

Reaction Steps

This compound was prepared according to the procedure of Example 25. A mixture of 5.8 g (0.0267 mole) of 4-chloro-1-(4-fluorophenoxy)-2-butanol, 5.1 g (0.0267 mole) of 1-(4-methoxyphenyl)piperazine, 9.4 g (0.089 mole) of anhydrous sodium carbonate, and 0.16 g of potassium iodide in a total volume of 200 ml of 1-butanol gave a brown oil. Upon trituration with petroleum ether (30°-60° C.), the oil solidified. The collected solid was recrystallized from isopropyl ether to yield 6.4 g (64%) of white, crystalline solid, m.p. 78°-80° C.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS04882330
Source datasetuspto-grants-1989_11
ORD IDord-de49c15584334477b708e8adbf167fa7
Source noteuspto-grants-1989_11