Vanillin → 4-Ethoxy-3-methoxybenzaldehyde
Reaction equation
[CH3:1][O:2][C:3]1[CH:4]=[C:5]([CH:10]=[O:11])[CH:6]=[CH:7][C:8]=1[OH:9].[OH-].[Na+].[CH2:14](I)[CH3:15]>O>[CH3:1][O:2][C:3]1[CH:4]=[C:5]([CH:6]=[CH:7][C:8]=1[O:9][CH2:14][CH3:15])[CH:10]=[O:11]Participants
5
Reactant 3
Product 1
Reagents, catalysts & solvents 1
Procedure
To a solution of 30.4 g (0.2 mole) of vanilline, 12 g (0.3 mole) of sodium hydroxide and 300 ml of water, then 37.4 g (0.24 mole) of ethyl iodide are added. The reaction mixture is heated to boiling for 15 hours, then cooled and extracted with benzene. The extract is evaporated. The crude residue is dissolved in 110 ml of a 25% aqueous sodium hydroxide solution, clarified with activated charcoal and made alkaline to pH 12. The precipitated crystals are filtered, washed with water and dried. Thus 24.8 g of 3-methoxy-4-ethoxy-benzaldehyde are obtained, yield 69%, m.p.: 65°-67° C.
Workup
- temperatureThe reaction mixture is heated
- temperaturecooled
- extractionextracted with benzene
- customThe extract is evaporated
- dissolutionThe crude residue is dissolved in 110 ml of a 25% aqueous sodium hydroxide solution
- filtrationThe precipitated crystals are filtered
- washwashed with water
- customdried
Sources & evidence
- ORD record
- ord-6454abf2cb37410ba522734900b5f173
- Source dataset
- uspto-grants-1989_11
- Patent number
- US04883798
Reaction notes
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