Benzoic Acid → Biphenyl

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Reaction Steps

In step 1 of Scheme A, nitrobenzoic acid a is subject to iodination under sulfuric acid conditions to afford iodo-nitrobenzoic acid b. Benzoic acid compound b is reacted with arylboronic acid compound c in the presence of tetrakis-triphenylphosphine)palladium catalyst to afford biphenyl acid compound d. The acid group of biphenyl acid d is protected by esterification in step 3 to form biphenyl acid methyl ester e. Biphenyl ester e is then subject to reduction to form biphenylamine f in step 4. An iodination reaction is carried out in step 5 by treating biphenylamine f with methylene iodide or like iodination reagent to afford iodo compound g. In step 6 iodo compound g is treated with thiadiazole h in the presence of palladium catalyst to give thiadiazole ester compound i. Compound i then undergoes base-catalyzed hydrolysis in step 7 to give the corresponding carboxylic acid compound j. Compound j is then reacted with amine k to provide thiazole amide compound m, which is a compound of formula I in accordance with the invention.

Provenance & Evidence