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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 1642337Generated: November 1, 2026

Ibudilast → 2-Isopropylpyrazolo[1,5-a]pyridine

https://huagongshe.com/reaction/1642337

Reaction equation

Participants

RoleNameHCIDCharge
ReactantIbudilastHCID 3671—
ReactantIsobutyraldehydeHCID 6561—
Reactant2-Isopropylpyrazolo[1,5-a]pyridineHCID 11378658—
Reactant2-Amino-1-(2-propan-2-ylpyrazolo[1,5-a]pyridin-3-yl)propan-1-oneHCID 23658966—
Product2-Isopropylpyrazolo[1,5-a]pyridineHCID 11378658—
Product2-Amino-1-(2-propan-2-ylpyrazolo[1,5-a]pyridin-3-yl)propan-1-oneHCID 23658966—
Product2-Isopropylpyrazolo[1,5-a]pyridine-3-carboxylic acidHCID 57837459—

Reaction Steps

According to one approach, therefore, the desired S-enantiomer of AV1013 is prepared by chiral resolution of the corresponding racemic mixture. As shown in FIG. 6, and described in the Example 1 below, synthesis of AV1013 involves several steps. The first step involves the synthesis of 2-chloro-nor-methylibudilast using either ibudilast (2-methyl-1-(2-isopropylpyrazolo[1,5-a]pyridin-3-yl)propan-1-one) or the corresponding 3-carboxylic acid (2-isopropyl-pyrazolo[1,5-a]pyridin-3-carboxylic acid, ibudilast acid) as the starting material. Thus, reacting ibudilast with an aqueous solution of a strong inorganic acid, for example, 50% aqueous sulfuric gave isopropylpyrazolo[1,5-a]pyridine (IPPP) following a loss of its 3-ring substituent (2-methyl-propan-1-one). Alternatively IPPP is obtained via the decarboxylation of 2-isopropyl-pyrazolo[1,5-a]pyridin-3-carboxylic acid under acidic conditions. See, Example 1, method 2, step 1.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS08119657B2
Source datasetuspto-grants-2012_02
ORD IDord-7ce12f2ff7c744f4aba5a2fd737f4c0f
Source noteuspto-grants-2012_02