HRID1642999

反应详情

EQUATION

反应方程式

HRID 1642999 的结构方程式

PROCEDURE

实验过程

100 mg (0.26 mmol) of the compound from Example 147A and 60 mg (0.39 mmol) of the compound from Example 73A were reacted according to the General Method 2. Yield: 75 mg (57% of theory)