HRID1646334

反应详情

EQUATION

反应方程式

HRID 1646334 的结构方程式

PROCEDURE

实验过程

Using a similar procedure to that described in Example 1, but starting from 2-ethylhexanoyl chloride and (A), there was obtained the title compound in 6% yield; partial NMR: 0.84 (m,6 H, 2×CH3), 1.24 [m,6 H, (CH2)3 ], 2.24 (m,1 H, CHCON), 10.78 (d,1 H, NH).