HRID1646933

反应详情

EQUATION

反应方程式

HRID 1646933 的结构方程式

AUXILIARIES

试剂、催化剂与溶剂

1

CONDITIONS

反应条件

温度
60 °C

PROCEDURE

实验过程

To a solution of 40 ml of butanol that had reacted with 0.5 g of Na (0.022 mol) was added 0.78 g of (7) (0.033 mol). The reaction was heated to 60° C. for 1.5 h and the cooled reaction treated with 6 ml of 5 N HCl. The butanol was azeotroped off with water, the residue made basic with saturated aqueous K2CO3, and the mixture extracted 3× with 25 ml of CH2Cl2. The extracts were washed with brine, dried, and the solvent evaporated to give a yellow solid that was purified by radial chromatography eluting with 5% ethanol-0.5% NH4OH-CHCl3 to give 0.55 g of (18) as a yellowish solid. Recrystallization from ether gave a white solid, mp 107°-108° C. NMR ppm (CDCl3) 1.0 (3H, t), 1.15 (1H, m), 1.35-1.6 (4H, m), 1.85 (2H, m), 2.25 (1H, m), 2.37 (1H, bs), 2.75 (1H, m), 2.82-3.0 (3H, m), 3.05 (1H, m), 3.95 (1H, s), 4.2 (1H, d), 4.45 (2H, q), 8.0 (1H, d), 8.12 (1H, d). Anal. C15H23N3O2 requires C: 64.96; H: 8.36; N: 15.15%. Found C: 65.21; H: 8.11; N: 15.25%.

WORKUP

后处理

  1. customthe cooled reaction
  2. customThe butanol was azeotroped off with water
  3. extractionthe mixture extracted 3× with 25 ml of CH2Cl2
  4. washThe extracts were washed with brine
  5. customdried
  6. customthe solvent evaporated
  7. customto give a yellow solid
  8. customthat was purified by radial chromatography
  9. washeluting with 5% ethanol-0.5% NH4OH-CHCl3