Methanol → N,N-Bis(3-aminopropyl)dodecylamine
Reaction equation
[CH2:1]([NH2:13])[CH2:2][CH2:3][CH2:4][CH2:5][CH2:6][CH2:7][CH2:8][CH2:9][CH2:10][CH2:11][CH3:12].[C:14](#[N:17])[CH:15]=[CH2:16].CO>O.C(O)(=O)C>[NH2:17][CH2:14][CH2:15][CH2:16][N:13]([CH2:3][CH2:2][CH2:1][NH2:13])[CH2:1][CH2:2][CH2:3][CH2:4][CH2:5][CH2:6][CH2:7][CH2:8][CH2:9][CH2:10][CH2:11][CH3:12]Participants
6
Reactant 3
Product 1
Reagents, catalysts & solvents 2
Procedure
670 g of laurylamine (C12 -fraction: 73 mole %, and C14 -fraction: 23 mole %) were reacted in the manner already described in Example 1 with 373 g of acrylonitrile in 68 g of water, 34 g of methanol and 14 g of concentrated acetic acid, and the product was then hydrogenated. 2,020 g of bis-(3-aminopropyl)-laurylamine were obtained after the hydrogenation. 954 g of this triamine were condensed with 640 g of ethylene oxide. 1,590 g of bis-(3-aminopropyl)-laurylamine ethoxylate (99%) were obtained. 257 g of this ethoxylate and 538 g of water were reacted with 146 g of 70% by weight strength H2O2. The triamine-trioxide was obtained in 935 g of a 30% by weight strength aqueous solution.
Sources & evidence
- ORD record
- ord-0298ce8dc1774378b454b153852d1766
- Source dataset
- uspto-grants-1983_11
- Patent number
- US04415488
Reaction notes
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