Ethanethiol → HCID 14013757, compound

HRID 1649662Notes

Reaction equation

HRID 1649662 reaction equation
[F:1][C:2]([F:24])([F:23])[C:3]1[C:8]([C:9]([O:11][CH2:12][CH3:13])=[O:10])=[C:7](Cl)[C:6]([C:15]([O:17][CH3:18])=[O:16])=[C:5]([C:19]([F:22])([F:21])[F:20])[N:4]=1.C([O-])([O-])=O.[K+].[K+].[CH2:31]([SH:33])[CH3:32]>CC(C)=O>[CH2:31]([S:33][C:7]1[C:6]([C:15]([O:17][CH3:18])=[O:16])=[C:5]([C:19]([F:20])([F:21])[F:22])[N:4]=[C:3]([C:2]([F:24])([F:23])[F:1])[C:8]=1[C:9]([O:11][CH2:12][CH3:13])=[O:10])[CH3:32]

Participants

5

Reactant 3

HCID 6343EthanethiolHCID 11430Potassium CarbonateHCID 14013761HCID 14013761, compound

Product 1

HCID 14013757HCID 14013757, compoundYield 58.8%

Reagents, catalysts & solvents 1

HCID 180AcetoneSolvent

Procedure

This material was prepared as described in Example 11: 3.36 g (0.009 mol) of product of Example 27, 0.86 g (0.006 mol) of K2CO3 and 12 ml (0.180 mol) of ethanethiol in 25 ml of acetone were reacted affording an orange oil which was kugelrohr distilled at 33 Pa, pot temperature 79° C. to give 2.11 g (58.8%) of product as a clear oil, nD25 1.4507.

Workup

  1. customThis material was prepared
  2. customaffording an orange oil which
  3. distillationwas kugelrohr distilled at 33 Pa, pot temperature 79° C.

Sources & evidence

ORD record
ord-8725fbf0a2d44c9da7b64d2f9fba2949
Source dataset
uspto-grants-1990_05
Patent number
US04921530

Reaction notes

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