Acetic Acid → 3-(2-(4-Isopropyl-2-thiazolyl))ethenylbenzoic acid
Reaction equation
[C:1]([C:3]1[CH:4]=[C:5]([CH:9]=[CH:10][C:11]2[S:12][CH:13]=[C:14]([CH:16]([CH3:18])[CH3:17])[N:15]=2)[CH:6]=CC=1)#N.O.[C:20]([OH:23])(=[O:22])[CH3:21]>Cl>[CH:16]([C:14]1[N:15]=[C:11]([CH:10]=[CH:9][C:5]2[CH:6]=[C:21]([CH:1]=[CH:3][CH:4]=2)[C:20]([OH:23])=[O:22])[S:12][CH:13]=1)([CH3:18])[CH3:17]Participants
5
Reactant 3
Product 1
Reagents, catalysts & solvents 1
Conditions
- Temperature
- 100 °C
Procedure
2-(2-(3-Cyanophenyl)ethenyl)-4-isopropylthiazole prepared in Synthetic Example (2.54 g, 10.0 mmol) was dissolved in a mixed solvent of acetic acid (5 ml) and concentrated hydrochloric acid (10 ml) and the resulting mixture was heated under stirring at 100° C. for 4 hours. After water was added, the reaction mixture was extracted with ethyl acetate and dried. The solvent was distilled out to afford the indicated compound (2.51 g) with a yield of 92%.
Workup
- temperaturethe resulting mixture was heated
- extractionthe reaction mixture was extracted with ethyl acetate
- customdried
- distillationThe solvent was distilled out
Sources & evidence
- ORD record
- ord-95717dc694a84d41b10adb14086e4e04
- Source dataset
- uspto-grants-1990_05
- Patent number
- US04925861
Reaction notes
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