Iodine → Hexahelicene
Reaction equation
II.[CH:3]([C:11]1[CH:20]=[CH:19][C:18]2[C:13](=[CH:14][C:15]([CH:21]=[CH:22][C:23]3[CH:28]=[CH:27][CH:26]=[CH:25][CH:24]=3)=[CH:16][CH:17]=2)[CH:12]=1)=[CH:4][C:5]1[CH:10]=[CH:9][CH:8]=[CH:7][CH:6]=1>>[CH:27]1[C:28]2[C:23](=[CH:22][CH:21]=[C:15]3[C:14]=2[C:13]2[C:18](=[CH:19][CH:20]=[C:11]4[C:12]=2[C:6]2[C:5](=[CH:10][CH:9]=[CH:8][CH:7]=2)[CH:4]=[CH:3]4)[CH:17]=[CH:16]3)[CH:24]=[CH:25][CH:26]=1Participants
3
Reactant 2
Product 1
Procedure
A small amount of iodine was added to a solution of 0.2 g/l of 2,7-bis(styryl)naphthalene, and the solution was irradiated with light from a high-pressure mercury lamp for 2 hr and then subjected to silica gel chromatography, and the separated product was recrystallized from benzene/ethanol as a solvent to obtain hexahelicene.
Workup
- customthe solution was irradiated with light from a high-pressure mercury lamp for 2 hr
- customthe separated product was recrystallized from benzene/ethanol as a solvent
Sources & evidence
- ORD record
- ord-2dfb376b25e848509513035bc1e51582
- Source dataset
- uspto-grants-1995_04
- Patent number
- US05403520
Reaction notes
Loading…