Hydrochloric Acid → 6-Methoxynicotinic acid
Reaction equation
C[C:2]1[CH:10]=[CH:9][C:5]([C:6]([OH:8])=[O:7])=[CH:4][N:3]=1.[OH-].[Na+].Cl.[CH2:14]([OH:16])C>>[CH3:14][O:16][C:2]1[CH:10]=[CH:9][C:5]([C:6]([OH:8])=[O:7])=[CH:4][N:3]=1Participants
5
Conditions
- Temperature
- 60 °C
Procedure
To a solution of 6-methylnicotinic acid (35 mg) in ethanol (1 mL) was added 2N sodium hydroxide solution (0.14 mL) and the mixture was stirred at 60° C. for 2 hours. After cooling to room temperature, to the reaction mixture was added 5N HCl (0.06 mL) and the mixture was evaporated in vacuo to give 6-methyloxynicotinic acid. The product was treated in the same manner as described in Example 3 to give (3R)-1-[bis-(4-chlorophenyl)methyl]-3-[(6-methoxynicotinoyl)amino]pyrrolidine (28.0 mg; yield: 61%) as a powder.
Workup
- temperatureAfter cooling to room temperature, to the reaction mixture
- customthe mixture was evaporated in vacuo
Sources & evidence
- ORD record
- ord-259c05d757194b679be8d1c69279bbe3
- Source dataset
- uspto-grants-2011_10
- Patent number
- US08034949B2
Reaction notes
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