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HRID1681274

反应详情

EQUATION

反应方程式

HRID 1681274 的结构方程式

REACTANTS

反应物

2
结构：CCCCCCCC/C=C\CCCCCCCC(=O)OCC(O)CO
HCID5283468

Glycerol 1-monooleate

C21H40O4

2 次

结构：C[C@H](CCC(=O)NCCS(=O)(=O)[O-])[C@H]1CC[C@H]2[C@@H]3[C@H](O)C[C@@H]4C[C@H](O)CC[C@]4(C)[C@H]3C[C@H](O)[C@]12C.[Na+]
HCID23666345

未命名化合物

4 次

PRODUCTS

生成物

1
结构：CCCCCCCC/C=C\CCCCCCCC(=O)OCC(O)CO.C[C@H](CCC(=O)NCCS(=O)(=O)[O-])[C@H]1CC[C@H]2[C@@H]3[C@H](O)C[C@@H]4C[C@H](O)CC[C@]4(C)[C@H]3C[C@H](O)[C@]12C.[Na+]
HCID131717675

未命名化合物

AUXILIARIES

试剂、催化剂与溶剂

1
结构：O
溶剂HCID962

Water

H2O

PROCEDURE

实验过程

860 mg of taurocholic acid was dissolved in 40 ml of de-ionized water. Then, 570.6 mg of monoolein was slowly added to the taurocholic acid solution using an ice bath on a sonic mixer. The final monolein and taurocholic acid concentration was 40 mM (the molecular weight of taurocholic acid is 537.7 and that of monoolein is 356.5). The mixture was stored at 10° C. until used.

WORKUP

后处理

  1. customwas stored at 10° C.