1-Bromo-2-methylpropane → HCID 67276389, compound

Participants

Reaction Steps

In a manner analogous to example 1 c, the process is carried out by a reaction of 4 g (16 mmol) of (4-bromo-2-tert-butylphenyl)ethylamine (example 1b) with 1.4 g (34 mmol) of 60% sodium hydride and with 3.7 ml (34 mmol) of 1-bromo-2-methylpropane. 1.5 g of (4-bromo-2-tert-butylphenyl)ethylisobutylamine are obtained in the form of an oil (yield=30%).

Provenance & Evidence