Benzyl Bromide → HCID 17797526, compound

HRID 1699782Notes

Reaction equation

HRID 1699782 reaction equation
[F:1][C:2]1[CH:3]=[C:4]([C:10]2[C:15]([C:16]3[CH:21]=[CH:20][C:19]([O:22][CH3:23])=[CH:18][CH:17]=3)=[N:14][NH:13][C:12](=[O:24])[CH:11]=2)[CH:5]=[CH:6][C:7]=1[O:8][CH3:9].[CH2:25](Br)[C:26]1[CH:31]=[CH:30][CH:29]=[CH:28][CH:27]=1>>[CH2:25]([N:13]1[C:12](=[O:24])[CH:11]=[C:10]([C:4]2[CH:5]=[CH:6][C:7]([O:8][CH3:9])=[C:2]([F:1])[CH:3]=2)[C:15]([C:16]2[CH:17]=[CH:18][C:19]([O:22][CH3:23])=[CH:20][CH:21]=2)=[N:14]1)[C:26]1[CH:31]=[CH:30][CH:29]=[CH:28][CH:27]=1

Participants

3

Reactant 2

HCID 7498Benzyl BromideHCID 18369307HCID 18369307, compound

Product 1

HCID 17797526HCID 17797526, compoundYield 95.6%

Procedure

Using 5-(3-fluoro-4-methoxyphenyl)-6-(4-methoxyphenyl)-2H-pyridazin-3-one and benzyl bromide as starting materials, the procedures of Example 12 were repeated likewise, whereby the title compound was obtained in a yield of 95.6%.

Sources & evidence

ORD record
ord-317e9ff2784a4361b56ebc35566c1801
Source dataset
uspto-grants-2002_02
Patent number
US06348468B1

Reaction notes

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