Sodium Iodide → HCID 14977896, compound

HRID 1703967Notes

Reaction equation

HRID 1703967 reaction equation
[CH3:1][O:2][C:3]1[CH:8]=[CH:7][C:6]([CH2:9][CH2:10][CH2:11][CH2:12][CH2:13][CH2:14]Br)=[CH:5][CH:4]=1.[I-:16].[Na+]>CC(=O)CC>[CH3:1][O:2][C:3]1[CH:8]=[CH:7][C:6]([CH2:9][CH2:10][CH2:11][CH2:12][CH2:13][CH2:14][I:16])=[CH:5][CH:4]=1

Participants

4

Procedure

6-(4-Methoxyphenyl)hexyl iodide [VIa; Ar is 4-CH3OC6H4, R is H] was prepared from 16.3 g. of 6-(4-methoxyphenyl)hexyl bromide (Preparation C10) and 9.93 g. of sodium iodide in 325 ml. of 2-butanone, to give 19.3 g. of product as a pale yellow oil.

Sources & evidence

ORD record
ord-2ef42bbcdbfb4602849a60a6b9b9ceea
Source dataset
uspto-grants-1978_11
Patent number
US04125541

Reaction notes

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