2-Bromoethyl methyl ether → HCID 23035278, compound

HRID 1709990Notes

Reaction equation

HRID 1709990 reaction equation
[OH:1][C:2]1[CH:17]=[CH:16][C:15]([O:18][CH2:19][C:20]([F:23])([F:22])[F:21])=[CH:14][C:3]=1[C:4]([NH:6][CH2:7][C:8]1[CH:13]=[CH:12][CH:11]=[CH:10][N:9]=1)=[O:5].[CH3:24][O:25][CH2:26][CH2:27]Br>>[CH3:24][O:25][CH2:26][CH2:27][O:1][C:2]1[CH:17]=[CH:16][C:15]([O:18][CH2:19][C:20]([F:23])([F:21])[F:22])=[CH:14][C:3]=1[C:4]([NH:6][CH2:7][C:8]1[CH:13]=[CH:12][CH:11]=[CH:10][N:9]=1)=[O:5]

Participants

3

Reactant 2

HCID 809722-Bromoethyl methyl etherHCID 15055922HCID 15055922, compound

Product 1

HCID 23035278HCID 23035278, compoundYield 67.6%

Procedure

Using the general method of Example I Part A, 6.5 g (0.02 mole) of 2-hydroxy-N-(2-pyridylmethyl)-5-(2,2,2-trifluoroethoxy)benzamide was reacted with 3.9 g (0.028 mole) of 2-bromoethyl methyl ether to give 5.2 g of white crystalline 2-(2-methoxyethoxy)-N-(2-pyridylmethyl)-5-(2,2,2-trifluoroethoxy)benzamide, m.p. 104°-107° C.

Sources & evidence

ORD record
ord-33b26875fd4748769b524f3ddbb9d25a
Source dataset
uspto-grants-1990_08
Patent number
US04952574

Reaction notes

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