HRID1724885

反应详情

EQUATION

反应方程式

REACTANTS

反应物

HCID180

Acetone

C3H6O

HCID313

Hydrochloric Acid

ClH

结构：CCc1c2c(nc3ccc(OC(=O)N4CCC(N5CCCCC5)CC4)cc13)-c1cc3c(c(=O)n1C2)COC(=O)[C@]3(O)CC

HCID60838

Irinotecan

C33H38N4O6

PRODUCTS

生成物

结构：CCc1c2c(nc3ccc(OC(=O)N4CCC(N5CCCCC5)CC4)cc13)-c1cc3c(c(=O)n1C2)COC(=O)[C@]3(O)CC.Cl

HCID74990

Irinotecan hydrochloride

C33H39ClN4O6

AUXILIARIES

试剂、催化剂与溶剂

溶剂HCID6342

Acetonitrile

C2H3N

CONDITIONS

反应条件

温度: 22 °C

PROCEDURE

实验过程

Irinotecan was suspended in acetonitrile or acetone in accordance with the amounts shown in Table 1 and dissolved by adding, 6 mol/L hydrochloric acid. To each mixture solution, 1 mg of c-type crystals separately prepared was added and the solution was stirred at 22° C. for 25 to 46 hours. The formed crystals were obtained by filtration, dried under reduced pressure, and subjected to a moisture absorption process performed by a saturated aqueous sodium chloride solution method until the crystals showed constant weight (about 80 hours). In this manner, the crystals of irinotecan hydrochloride were obtained.

WORKUP

后处理

dissolutiondissolved
additionby adding
customTo each mixture solution, 1 mg of c-type crystals separately prepared
additionwas added
customThe formed crystals were obtained by filtration
customdried under reduced pressure
customweight (about 80 hours)

来源与证据

来源类型: Open Reaction Database
ORD 记录: ord-eda3c6602abe47ebbcf0f0ec640f3d21
来源数据集: uspto-grants-2009_02
DOI: 10.6084/m9.figshare.5104873.v1
专利: US07488825B2
来源说明: uspto-grants-2009_02

反应 SMILES

[CH3:1][CH2:2][C:3]1[C:12]2[CH2:13][N:14]3[C:19](=[O:20])[C:18]4[CH2:21][O:22][C:23]([C@:25]([OH:28])([CH2:26][CH3:27])[C:17]=4[CH:16]=[C:15]3[C:11]=2[N:10]=[C:9]2[C:4]=1[CH:5]=[C:6]([O:29][C:30]([N:32]1[CH2:37][CH2:36][CH:35]([N:38]3[CH2:43][CH2:42][CH2:41][CH2:40][CH2:39]3)[CH2:34][CH2:33]1)=[O:31])[CH:7]=[CH:8]2)=[O:24].CC(C)=O.[ClH:48]>C(#N)C>[CH3:1][CH2:2][C:3]1[C:12]2[CH2:13][N:14]3[C:19](=[O:20])[C:18]4[CH2:21][O:22][C:23]([C@:25]([OH:28])([CH2:26][CH3:27])[C:17]=4[CH:16]=[C:15]3[C:11]=2[N:10]=[C:9]2[C:4]=1[CH:5]=[C:6]([O:29][C:30]([N:32]1[CH2:33][CH2:34][CH:35]([N:38]3[CH2:43][CH2:42][CH2:41][CH2:40][CH2:39]3)[CH2:36][CH2:37]1)=[O:31])[CH:7]=[CH:8]2)=[O:24].[ClH:48]