Sodium Iodide → 4-(3-Iodopropoxy)benzoic acid, methyl ester

HRID 1736437Notes

Reaction equation

HRID 1736437 reaction equation
Cl[CH2:2][CH2:3][CH2:4][O:5][C:6]1[CH:15]=[CH:14][C:9]([C:10]([O:12][CH3:13])=[O:11])=[CH:8][CH:7]=1.[I-:16].[Na+]>CC(C)=O.C(OCC)C>[I:16][CH2:2][CH2:3][CH2:4][O:5][C:6]1[CH:15]=[CH:14][C:9]([C:10]([O:12][CH3:13])=[O:11])=[CH:8][CH:7]=1

Participants

5

Procedure

Dissolve 4-(3-chloropropoxy)benzoic acid, methyl ester (6.97 g, 30.5 mmol) in anhydrous acetone (100 mL) and add powdered sodium iodide (16.0 g, 107 mmol). Heat at reflux under an argon atmosphere for 38 hours. Dilute with ethyl ether (100 mL) and filter through Celite® filter aid. Wash the filtrate with water and brine, then dry (MgSO4). Evaporate the solvent in vacuo to give 4-(3-iodopropoxy)benzoic acid, methyl ester as a yellow oil.

Workup

  1. temperatureHeat
  2. temperatureat reflux under an argon atmosphere for 38 hours
  3. filtrationfilter through Celite®
  4. filtrationfilter aid
  5. washWash the filtrate with water and brine
  6. dry with materialdry (MgSO4)
  7. customEvaporate the solvent in vacuo

Sources & evidence

ORD record
ord-25af5a60b17f4f02b1428451900c7d5c
Source dataset
uspto-grants-1996_07
Patent number
US05541200

Reaction notes

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