Hydrogen iodide → 5-Benzothiazolol
Reaction equation
C[O:2][C:3]1[CH:4]=[CH:5][C:6]2[S:10][CH:9]=[N:8][C:7]=2[CH:11]=1.I>O>[S:10]1[C:6]2[CH:5]=[CH:4][C:3]([OH:2])=[CH:11][C:7]=2[N:8]=[CH:9]1Participants
4
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Procedure
A mixture of intermediate 24 (272 mg, 1.65 mmol) and hydroiodic acid (45%, 2 mL) was heated to reflux for 5 h. The mixture was diluted with water and filtered. The filtrate was neutralized and the solids were filtered, washed with water, and combined to give benzo[d]thiazol-5-ol (intermediate 25) (206 mg, 83%). HPLC: 99%, RT 2.038 min. MS (ESI) m/z 152.1 [M+H]+.
Workup
- temperaturewas heated
- temperatureto reflux for 5 h
- filtrationfiltered
- filtrationthe solids were filtered
- washwashed with water
Sources & evidence
- ORD record
- ord-519ee086812f4c4b9d536035960bc5f4
- Source dataset
- uspto-grants-2015_10
- Patent number
- US09156822B2
Reaction notes
Loading…