3-Methoxy-4-nitrobenzoic acid → Methyl 4-amino-3-fluorobenzoate
Reaction equation
[F:1][C:2]1[CH:3]=[C:4]([CH:9]=[CH:10][C:11]=1[N+:12]([O-])=O)[C:5]([O:7][CH3:8])=[O:6].COC1C=C(C=CC=1[N+]([O-])=O)C(O)=O>[Pd].C(OCC)(=O)C>[NH2:12][C:11]1[CH:10]=[CH:9][C:4]([C:5]([O:7][CH3:8])=[O:6])=[CH:3][C:2]=1[F:1]Participants
5
Reactant 2
Product 1
Reagents, catalysts & solvents 2
Procedure
150 mg of 10% palladium on charcoal was added to a solution of the above mixture consisting of methyl 3-fluoro-4-nitrobenzoate and 3-methoxy-4-nitrobenzoic acid (1.7 g) in 50 mL ethyl acetate and maintained under H2 (45 psi) for two hours. The reaction mixture was filtered over Celite and concentrated in vacuo. The product was purified by flash chromatography (SiO2, 10% methanol/dichloromethane), giving 0.7 g of methyl 4-amino-3-fluorobenzoate as an off-white solid.
Workup
- temperaturemaintained under H2 (45 psi) for two hours
- filtrationThe reaction mixture was filtered over Celite
- concentrationconcentrated in vacuo
- customThe product was purified by flash chromatography (SiO2, 10% methanol/dichloromethane)
Sources & evidence
- ORD record
- ord-592fd21a0f904438bf2a92f4a40595e4
- Source dataset
- uspto-grants-2005_01
- Patent number
- US06844466B2
Reaction notes
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