Hydrochloric Acid → 6-Chloro-2-(4-fluoroindolin-2-yl)pyridin-3-ol

HRID 1776849Notes

Reaction equation

HRID 1776849 reaction equation
[Cl:1][C:2]1[N:7]=[C:6]([C:8]2[NH:9][C:10]3[C:15]([CH:16]=2)=[C:14]([F:17])[CH:13]=[CH:12][CH:11]=3)[C:5]([OH:18])=[CH:4][CH:3]=1.Cl.[OH-].[Na+]>CCO>[Cl:1][C:2]1[N:7]=[C:6]([CH:8]2[CH2:16][C:15]3[C:10](=[CH:11][CH:12]=[CH:13][C:14]=3[F:17])[NH:9]2)[C:5]([OH:18])=[CH:4][CH:3]=1

Participants

5

Reactant 3

HCID 313Hydrochloric AcidHCID 14798Sodium HydroxideHCID 867262926-chloro-2-(4-fluoro-1H-indol-2-yl)pyridin-3-ol

Product 1

HCID 867262936-Chloro-2-(4-fluoroindolin-2-yl)pyridin-3-olYield 80%

Reagents, catalysts & solvents 1

HCID 702EthanolSolvent

Procedure

A mixture of 6-chloro-2-(4-fluoro-1H-indol-2-yl)pyridin-3-ol (10 g, 38 mmol) and metal Sn (23 g, 190 mmol) in CH3CH2OH/con. HCl (60 mL/40 mL) was stirred under reflux for 3 hours. The mixture was cooled to room temperature and adjusted to pH=7 by saturated NaOH and filtered though a Celit pad. The filtrate was extracted with EtOAc, washed by brine, dried over Na2SO4 and concentrated in vacuo. The resulting residue was purified using silica gel chromatography (petroleum ether:EtOAc=10:1) to get 6-chloro-2-(4-fluoroindolin-2-yl)pyridin-3-ol (8 g, yield: 80%). 1H-NMR (CDCl3, 400 MHz) δ 9.86 (s, 1H), 7.10˜7.20 (m, 3H), 6.33˜6.91 (m, 2H), 5.15˜5.21 (m, 1H), 4.61 (s, 1H), 3.65˜3.71 (m, 1H), 3.04˜3.11 (m, 1H). MS (M+H)+: 265.

Workup

  1. temperatureunder reflux for 3 hours
  2. filtrationfiltered though a Celit pad
  3. extractionThe filtrate was extracted with EtOAc
  4. washwashed by brine
  5. dry with materialdried over Na2SO4
  6. concentrationconcentrated in vacuo
  7. customThe resulting residue was purified

Sources & evidence

ORD record
ord-807e9b9902d647359d27e99619788d9a
Source dataset
uspto-grants-2016_02
Patent number
US09265773B2

Reaction notes

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