Potassium Hydroxide → HCID 5276133, compound
Reaction equation
BrC1C=CC(O)=C(C2C=[CH:16][C:15]3[C:10](=[CH:11][CH:12]=[C:13]([C:18]4[N:22]([CH:23]5[CH2:28][CH2:27][CH2:26][CH2:25][CH2:24]5)[C:21]5[CH:29]=[CH:30][C:31]([C:33]([OH:35])=[O:34])=[CH:32][C:20]=5[N:19]=4)[CH:14]=3)[N:9]=2)C=1.[CH:37]1([C:43]2[CH:48]=[CH:47][C:46]([O:49][CH3:50])=[CH:45][C:44]=2[C:51](=O)[CH3:52])[CH2:42][CH2:41][CH2:40][CH2:39][CH2:38]1.[OH-].[K+]>C(O)C>[CH:23]1([N:22]2[C:21]3[CH:29]=[CH:30][C:31]([C:33]([OH:35])=[O:34])=[CH:32][C:20]=3[N:19]=[C:18]2[C:13]2[CH:14]=[C:15]3[C:10](=[CH:11][CH:12]=2)[N:9]=[C:51]([C:44]2[CH:45]=[C:46]([O:49][CH3:50])[CH:47]=[CH:48][C:43]=2[CH:37]2[CH2:42][CH2:41][CH2:40][CH2:39][CH2:38]2)[CH:52]=[CH:16]3)[CH2:24][CH2:25][CH2:26][CH2:27][CH2:28]1Participants
5
Procedure
Following the procedure and workup for Compound 354, Compound 354e (86 mg, 0.22 mmol) was reacted with Compound 545a (50 mg, 0.22 mmol) in ethanol (3 mL) using 10% w/v KOH in Ethanol (436 μL, 0.66 mmol) to produce the title compound (26 mg, 21% yield).
Sources & evidence
- ORD record
- ord-d561aa8de7184e83af868602a51ae444
- Source dataset
- uspto-grants-2009_03
- Patent number
- US07511145B2
Reaction notes
Loading…