Ethanethiol → HCID 13912577, compound
Reaction equation
[CH3:1][C:2]1[C:7]([C:8]([O:10][CH2:11][CH3:12])=[O:9])=[C:6]([C:13]2[CH:18]=[CH:17][CH:16]=[C:15]([N+:19]([O-:21])=[O:20])[CH:14]=2)[N:5]([S:22]([C:25]2[CH:30]=[CH:29][CH:28]=[CH:27][CH:26]=2)(=[O:24])=[O:23])[CH2:4][N:3]=1.FC(F)(F)C(O)=O.C([SH:40])C>ClCCl>[CH3:1][C:2]1[NH:3][C:4](=[S:40])[N:5]([S:22]([C:25]2[CH:30]=[CH:29][CH:28]=[CH:27][CH:26]=2)(=[O:24])=[O:23])[CH:6]([C:13]2[CH:18]=[CH:17][CH:16]=[C:15]([N+:19]([O-:21])=[O:20])[CH:14]=2)[C:7]=1[C:8]([O:10][CH2:11][CH3:12])=[O:9]Participants
5
Reactant 3
Product 1
Reagents, catalysts & solvents 1
Procedure
A solution of 0.95 g (0.0016 mole) of 1, 6-dihydro-2-[(4-methoxyphenyl)methyl]thio]-4-methyl -6-(3-nitrophenyl)-1-(phenylsulfonyl)-5pyrimidinecarboxylic acid, ethyl ester, 0.6 ml (0.0066 mole) of trifluoroacetic acid and 0.24 g (0.0037 mole) of ethanethiol in 20 ml of dichloromethane was stirred at room temperature overnight. The solvent was evaporated and the residue (solid) was treated with isopropyl ether to give 0.68 g of the title compound as a colorless solid, melting point 162°-164° C. Analysis Calc'd. for C20H19N3O6S2 : C, 52.04; H, 4.14; N, 9.10; S, 13.89. Found: C, 51.77; H, 4.09; N, 8.96; S, 13.71.
Workup
- customThe solvent was evaporated
- additionthe residue (solid) was treated with isopropyl ether
Sources & evidence
- ORD record
- ord-0a47d9448359468d91c08b73c213d4f4
- Source dataset
- uspto-grants-1987_08
- Patent number
- US04684656
Reaction notes
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