Ethyl Bromide → 2-Chloro-6-fluoro-4-ethoxy-benzylalcohol

HRID 1794160Notes

Reaction equation

[Cl:1][C:2]1[CH:3]=[C:4]([OH:11])[CH:5]=[C:6]([F:10])[C:7]=1[CH2:8][OH:9].[CH2:12](Br)[CH3:13]>>[Cl:1][C:2]1[CH:3]=[C:4]([O:11][CH2:12][CH3:13])[CH:5]=[C:6]([F:10])[C:7]=1[CH2:8][OH:9]

Participants

Reactant 2

HCID 6332Ethyl Bromide

HCID 222200093-Chloro-5-fluoro-4-(hydroxymethyl)phenol

Product 1

HCID 222198882-Chloro-6-fluoro-4-ethoxy-benzylalcoholYield 60%

Procedure

This compound was prepared from 3-chloro-5-fluoro-4-hydroxymethyl-phenol and ethylbromide according to the procedure described in Example 179 to give the product as a yellowish oil (209 mg, 60%); MS (EI): 204.1 (M)+.

Sources & evidence

ORD record: ord-c7ce4a6d9da646e5b50944f5e93efdfd
Source dataset: uspto-grants-2006_04
DOI: 10.6084/m9.figshare.5104873.v1
Patent number: US07022707B2

Reaction notes

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