huagongshe.com
HRID1804121

反应详情

EQUATION

反应方程式

HRID 1804121 的结构方程式

REACTANTS

反应物

2
结构：O=C(Cl)c1ccc(I)cc1
HCID74373

Benzoyl chloride, 4-iodo-

C7H4ClIO

结构：Cc1cc(C)c(N2CCNCC2)nc1C
HCID58484823

未命名化合物

PRODUCTS

生成物

1
结构：Cc1cc(C)c(N2CCN(C(=O)c3ccc(I)cc3)CC2)nc1C
HCID58484793

未命名化合物

收率 94.8%

PROCEDURE

实验过程

By reaction and treatment in the same manner as in Preparation Example 161 and using 1-(3,5,6-trimethylpyridin-2-yl)piperazine (4.39 g) described in Preparation Example 175 and 4-iodobenzoyl chloride (5.98 g), the title compound (8.82 g) was obtained.

WORKUP

后处理

  1. customBy reaction and treatment in the same manner
  2. customas in Preparation Example 161