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HRID1804122

反应详情

EQUATION

反应方程式

HRID 1804122 的结构方程式

REACTANTS

反应物

2
结构：O=C(Cl)c1ccc(I)cc1
HCID74373

Benzoyl chloride, 4-iodo-

C7H4ClIO

结构：CCc1cnc(N2CCNCC2)c(C)c1
HCID58484578

未命名化合物

PRODUCTS

生成物

1
结构：CCc1cnc(N2CCN(C(=O)c3ccc(I)cc3)CC2)c(C)c1
HCID58484605

未命名化合物

收率 90.5%

PROCEDURE

实验过程

By reaction and treatment in the same manner as in Preparation Example 161 and using 1-(5-ethyl-3-methylpyridin-2-yl)piperazine (2.46 g) described in Preparation Example 53 and 4-iodobenzoyl chloride (3.36 g), the title compound (4.72 g) was obtained.

WORKUP

后处理

  1. customBy reaction and treatment in the same manner
  2. customas in Preparation Example 161