Sodium Iodide → 3-Hydroxy-4-iodobenzoic acid
Reaction equation
[OH:1][C:2]1[CH:3]=[C:4]([CH:8]=[CH:9][CH:10]=1)[C:5]([OH:7])=[O:6].[I-:11].[Na+].Cl[O-].[Na+]>>[I:11][C:10]1[CH:9]=[CH:8][C:4]([C:5]([OH:7])=[O:6])=[CH:3][C:2]=1[OH:1]Participants
4
Procedure
3-Hydroxybenzoic acid (V) is iodinated in the presence of sodium iodide and of sodium hypochlorite in order to give 4-iodo-3-hydroxybenzoic acid (VI).
Sources & evidence
- ORD record
- ord-9e46445f3bb4443aaff1b59686b81d5c
- Source dataset
- uspto-grants-2013_01
- Patent number
- US08357819B2
Reaction notes
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