Hydrochloric Acid → 2-Ethyl-5-methyl-4-thiazolecarboxylic acid
Reaction equation
[CH2:1]([C:3]1[S:4][C:5]([CH3:13])=[C:6]([C:8]([O:10]CC)=[O:9])[N:7]=1)[CH3:2].[OH-].[Na+].Cl>C(O)C>[CH2:1]([C:3]1[S:4][C:5]([CH3:13])=[C:6]([C:8]([OH:10])=[O:9])[N:7]=1)[CH3:2]Participants
5
Reactant 3
Product 1
Reagents, catalysts & solvents 1
Procedure
8 g of ethyl 2-ethyl-5-methyl-1,3-thiazole-4-carboxylate was dissolved in 10 ml ethanol. 2 ml of 5N sodium hydroxide was added, followed by heating under reflux for 1 hour. The reaction solution was ice-cooled and neutralized with 2N hydrochloric acid, followed by extracting with ethyl acetate. The organic layer was washed with brine, dried over anhydrous magnesium sulfate and evapoarated, to give 0.8 g of 2-ethyl-5-methyl-1,3-thiazole-4-carboxylic acid.
Workup
- temperatureby heating
- temperatureunder reflux for 1 hour
- temperaturecooled
- extractionby extracting with ethyl acetate
- washThe organic layer was washed with brine
- dry with materialdried over anhydrous magnesium sulfate
Sources & evidence
- ORD record
- ord-931362bee4b64f798abf54c15c03da52
- Source dataset
- uspto-grants-2005_04
- Patent number
- US06884821B1
Reaction notes
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