HRID1840621

反应详情

EQUATION

反应方程式

HRID 1840621 的结构方程式

PROCEDURE

实验过程

The compound was prepared analogously to Example 10 from 170 mg (0.248 mmol) of the compound of Example 15, but was not converted into the hydrochloride by addition of hydrochloric acid. Yield: 160 mg (98%).