Aluminium lithium hydride → 2-(4-Chloro-3-methoxyphenyl)ethan-1-amine
Reaction equation
[Cl:1][C:2]1[CH:7]=[CH:6][C:5]([CH:8]=[CH:9][N+:10]([O-])=O)=[CH:4][C:3]=1[O:13][CH3:14].[H-].[H-].[H-].[H-].[Li+].[Al+3]>C1COCC1>[Cl:1][C:2]1[CH:7]=[CH:6][C:5]([CH2:8][CH2:9][NH2:10])=[CH:4][C:3]=1[O:13][CH3:14]Participants
4
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Procedure
1-Chloro-2-methoxy-4-(2-nitrovinyl)benzene (I-86a: 800 mg, 3.74 mmol) in dry THF (10 mL) was reacted with LAH (278 mg, 7.48 mmol) in dry THF (10 mL) to afford 700 mg of the product (100%).
Sources & evidence
- ORD record
- ord-a96beede3dc6489696a325fe2c48711e
- Source dataset
- uspto-grants-2015_02
- Patent number
- US08946260B2
Reaction notes
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