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HRID1856195

反应详情

EQUATION

反应方程式

HRID 1856195 的结构方程式

REACTANTS

反应物

3
结构：CC(=O)OC(C)=O
HCID7918

Acetic anhydride

C4H6O3

结构：Cn1c([N+](=O)[O-])cnc1C=O
HCID78487

Imidazole-2-carboxaldehyde, 1-methyl-5-nitro-

C5H5N3O3

结构：CCCCCCCCCCCCCc1nnc(C)s1
HCID23346374

2-Methyl-5-tridecyl-1,3,4-thiadiazole

C16H30N2S

PRODUCTS

生成物

1
结构：CCCCCCCCCCCCCc1nnc(C=Cc2ncc([N+](=O)[O-])n2C)s1
HCID53739186

未命名化合物

收率 56.6%

AUXILIARIES

试剂、催化剂与溶剂

2
结构：[Cl-].[Cl-].[Zn+2]
催化剂HCID3007855

Zinc chloride

Cl2Zn

结构：CC(=O)O
溶剂HCID176

Acetic Acid

C2H4O2

PROCEDURE

实验过程

8.45 g of 2-tridecyl-5-methyl-1,3,4-thiadiazole, 4.65 g of 1-methyl-5-nitroimidazole-2-carboxaldehyde and 0.5 g of zinc chloride are heated in 40 ml of acetic acid and 15 ml of acetic anhydride for 24 hours at reflux temperature. After the solvent has been removed, the residue is recrystallized from alcohol. 7.1 g of product is obtained, corresponding to 61% of the theory. The melting point is 91° C.

WORKUP

后处理

  1. customAfter the solvent has been removed
  2. customthe residue is recrystallized from alcohol