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HRID1864697

反应详情

EQUATION

反应方程式

HRID 1864697 的结构方程式

REACTANTS

反应物

2
结构：Cc1c(N=C=O)ccc(C#N)c1Cl
HCID16731849

未命名化合物

结构：CC(C)(C)OC(=O)N1CC[C@@H](O[Si](C)(C)C(C)(C)C)[C@]1(C)CO
HCID69019276

未命名化合物

PRODUCTS

生成物

1
结构：CC(C)(C)OC(=O)N1CC[C@H](O[Si](C)(C)C(C)(C)C)[C@@]1(C)CO
HCID59754210

未命名化合物

收率 68.9%

PROCEDURE

实验过程

Compound 4D (84.0 mg) was prepared from compound 4C (122 mg) and compound 1G (82.0 mg) following procedures analogous to those used in Example 1 for the preparation of compound 1H. LCMS: m/z 438 [M+H]+.