Methyl iodide → Methyl (E)-3-fluorocinnamate
Reaction equation
[F:1][C:2]1[CH:3]=[C:4]([CH:10]=[CH:11][CH:12]=1)/[CH:5]=[CH:6]/[C:7]([OH:9])=[O:8].IC.[C:15](=O)([O-])[O-].[Cs+].[Cs+]>CC(C)=O.C(OCC)(=O)C>[CH3:15][O:8][C:7](=[O:9])/[CH:6]=[CH:5]/[C:4]1[CH:10]=[CH:11][CH:12]=[C:2]([F:1])[CH:3]=1Participants
6
Reactant 3
Product 1
Reagents, catalysts & solvents 2
Conditions
- Temperature
- 65 °C
Procedure
To a mixture of trans-3-fluorocinnamic acid (50 g, 300 mmol) and iodomethane (300 mL) in acetone (1 L) was added portionwise cesium carbonate (147 g, 450 mmol, 1.5 equiv.), and the mixture was heated at 65° C. for 1.5 hours in a sealed reaction vessel. Upon cooling to room temperature, the reaction mixture was diluted with ethyl acetate (1 L), filtered through a pad of silica gel, and concentrated to give 47.33 g (87%) of trans-3-fluorocinnamic acid methyl ester as a colorless oil. MS (ES) m/z 180.0 (M+).
Workup
- temperatureUpon cooling to room temperature
- filtrationfiltered through a pad of silica gel
- concentrationconcentrated
Sources & evidence
- ORD record
- ord-a668c10366a94d0c863eb70a811d0462
- Source dataset
- uspto-grants-2009_12
- Patent number
- US07638512B2
Reaction notes
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