HRID1882235

反应详情

EQUATION

反应方程式

HRID 1882235 的结构方程式

PROCEDURE

实验过程

The title compound was prepared in 88% yield from example Compound 128 according to the procedure outlined for the preparation of Compound 124. MS (ES) [m+H] calc'd for C14H13N3O2, 256; found 256.