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HRID1904242

反应详情

EQUATION

反应方程式

HRID 1904242 的结构方程式

REACTANTS

反应物

2
结构：CCOCC(CC)Oc1ccc(CBr)cc1
HCID14671809

未命名化合物

结构：CC(C)(C)n1ncc(O)c(Cl)c1=O
HCID54686946

2-tert-Butyl-4-chloro-5-hydroxypyridazin-3(2H)-one

C8H11ClN2O2

PRODUCTS

生成物

1
结构：CCOCC(CC)Oc1ccc(COc2cnn(C(C)(C)C)c(=O)c2Cl)cc1
HCID14671810

未命名化合物

收率 24.8%

PROCEDURE

实验过程

Procedures similar to those in Preparation Example 8 were carried out by using 2.0 g of 2-t-butyl-4-chloro-5-hydroxy-3(2H)-pyridazinone and 3.1 g of 4-(2-ethoxy-1-ethylethoxy)-benzyl bromide to obtain 1.0 g of the aimed compound as an oil.

WORKUP

后处理

  1. customProcedures similar to those in Preparation Example 8