Chloroacetic Acid → 2-[2-(4-Fluorophenyl)ethoxy]acetic acid

HRID 1905965Notes

Reaction equation

HRID 1905965 reaction equation
[F:1][C:2]1[CH:10]=[CH:9][C:5]([CH2:6][CH2:7][OH:8])=[CH:4][CH:3]=1.Cl[CH2:12][C:13]([OH:15])=[O:14].CC1CCCCC1>>[F:1][C:2]1[CH:10]=[CH:9][C:5]([CH2:6][CH2:7][O:8][CH2:12][C:13]([OH:15])=[O:14])=[CH:4][CH:3]=1

Participants

4

Reactant 3

HCID 300Chloroacetic AcidHCID 7962MethylcyclohexaneHCID 820684-Fluorophenethyl Alcohol

Product 1

HCID 132089232-[2-(4-Fluorophenyl)ethoxy]acetic acidYield 79%

Procedure

7.0 g of 4-fluorophenethyl alcohol were reacted with 4.73 g of chloroacetic acid in a manner analogous to that described in Example 1(a) to give 7.8 g (79%) of 2-(4-fluorophenyl)ethoxyacetic acid of melting point 82°-85° C. (from methylcyclohexane).

Sources & evidence

ORD record
ord-391d245eecff439ab3cf621b91567243
Source dataset
uspto-grants-1987_03
Patent number
US04649160

Reaction notes

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