Chloroacetic Acid → 2-(4-Chlorophenyl)ethoxyacetic acid

HRID 1905980Notes

Reaction equation

HRID 1905980 reaction equation
[Cl:1][C:2]1[CH:10]=[CH:9][C:5]([CH2:6][CH2:7][OH:8])=[CH:4][CH:3]=1.Cl[CH2:12][C:13]([OH:15])=[O:14]>C(OCC)(=O)C.CCCCCC>[Cl:1][C:2]1[CH:10]=[CH:9][C:5]([CH2:6][CH2:7][O:8][CH2:12][C:13]([OH:15])=[O:14])=[CH:4][CH:3]=1

Participants

4

Reactant 2

HCID 300Chloroacetic AcidHCID 74647p-Chlorophenethylic alcohol

Product 1

HCID 132089252-(4-Chlorophenyl)ethoxyacetic acidYield 105.4%

Reagents, catalysts & solvents 1

HCID 21226206Ethyl acetate hexaneSolvent

Procedure

3.15 g of 4-chlorophenethyl alcohol were reacted with 2.2 g of chloroacetic acid in a manner analogous to that described in Example 1(a) to give 4.55 g (91%) of 2-(4-chlorophenyl)ethoxyacetic acid of melting point 75°-77° C. (from ethyl acetate/hexane).

Sources & evidence

ORD record
ord-f34e4f5159a84048b234e615cf405b11
Source dataset
uspto-grants-1987_03
Patent number
US04649160

Reaction notes

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