Chloroacetic Acid → 2-[2-(2,4-Difluorophenyl)ethoxy]acetic acid
Reaction equation
[F:1][C:2]1[CH:10]=[C:9]([F:11])[CH:8]=[CH:7][C:3]=1[CH2:4][CH2:5][OH:6].Cl[CH2:13][C:14]([OH:16])=[O:15]>>[F:1][C:2]1[CH:10]=[C:9]([F:11])[CH:8]=[CH:7][C:3]=1[CH2:4][CH2:5][O:6][CH2:13][C:14]([OH:16])=[O:15]Participants
3
Conditions
- Temperature
- 120 °C
Procedure
3.63 g of 2,4-difluorophenethyl alcohol were reacted with 2.17 g of chloroacetic acid in a manner analogous to that described in Example 1(a), except that the reaction mixture was heated at 120° C. for 1 hour, to give 2.7 g (54%) of 2-(2,4-difluorophenyl)ethoxyacetic acid in the form of an oil which was homogeneous according to chromatography.
Sources & evidence
- ORD record
- ord-1af4a45575fc4ec6904e5fe919aa2779
- Source dataset
- uspto-grants-1987_03
- Patent number
- US04649160
Reaction notes
Loading…