HRID1920627

反应详情

EQUATION

反应方程式

REACTANTS

反应物

HCID107

Hydrocinnamic acid

C9H10O2

结构：COc1ccc(C[C@H](NC(=O)OC(C)(C)C)C(=O)O)c(OC)c1OC

HCID60024443

未命名化合物

结构：CC(C)C[C@H](NC(=O)[C@@H](NC(=O)OC(C)(C)C)C(C)C)B1O[C@@H]2C[C@@H]3C[C@@H](C3(C)C)[C@]2(C)O1

HCID67492646

未命名化合物

PRODUCTS

生成物

结构：COc1ccc(C[C@H](NC(=O)CCc2ccccc2)C(=O)N[C@H](C(=O)N[C@@H](CC(C)C)B2O[C@@H]3C[C@@H]4C[C@@H](C4(C)C)[C@]3(C)O2)C(C)C)c(OC)c1OC

HCID20823725

未命名化合物

PROCEDURE

实验过程

The title compound is prepared from {(S)-2-Methyl-1-[(R)-3-methyl-1-((1S,2S,6R,8S)-2,9,9-trimethyl-3,5-dioxa-4-bora-tricyclo[6.1.1.02,6]dec-4-yl)-butylcarbamoyl]-propyl}-carbamic acid tert-butyl ester by reiteration of the 2-step (deprotection/coupling) procedure described in example 1 but using (S)-2-(tert-butyloxycarbonyl-amino)-3-(2,3,4-trimethoxy-phenyl)-propionic acid and 3-Phenyl-propionic acid (Fluka, Buchs, Switzerland) as the partners in each coupling reaction (step B, example 1), respectively.

WORKUP

后处理

customin each coupling reaction (step B, example 1)

来源与证据

来源类型: Open Reaction Database
ORD 记录: ord-f5ab2a2d1b8d4dbca6276543d64c36a8
来源数据集: uspto-grants-2012_05
DOI: 10.6084/m9.figshare.5104873.v1
专利: US08173128B2
来源说明: uspto-grants-2012_05

反应 SMILES

C(O[C:6](=[O:33])[NH:7][C@H:8]([C:12](=[O:32])[NH:13][C@H:14]([B:19]1[O:27][C@H:26]2[C@:21]([CH3:31])([C@H:22]3[CH2:28][C@@H:24]([CH2:25]2)[C:23]3([CH3:30])[CH3:29])[O:20]1)[CH2:15][CH:16]([CH3:18])[CH3:17])[CH:9]([CH3:11])[CH3:10])(C)(C)C.C(O[C:39]([NH:41][C@@H:42]([CH2:46][C:47]1[CH:52]=[CH:51][C:50]([O:53][CH3:54])=[C:49]([O:55][CH3:56])[C:48]=1[O:57][CH3:58])C(O)=O)=[O:40])(C)(C)C.[C:59]1([CH2:65][CH2:66]C(O)=O)[CH:64]=[CH:63][CH:62]=[CH:61][CH:60]=1>>[CH3:11][CH:9]([CH3:10])[C@H:8]([NH:7][C:6](=[O:33])[C@@H:42]([NH:41][C:39](=[O:40])[CH2:66][CH2:65][C:59]1[CH:64]=[CH:63][CH:62]=[CH:61][CH:60]=1)[CH2:46][C:47]1[CH:52]=[CH:51][C:50]([O:53][CH3:54])=[C:49]([O:55][CH3:56])[C:48]=1[O:57][CH3:58])[C:12]([NH:13][C@H:14]([B:19]1[O:27][C@H:26]2[C@:21]([CH3:31])([C@H:22]3[CH2:28][C@@H:24]([CH2:25]2)[C:23]3([CH3:29])[CH3:30])[O:20]1)[CH2:15][CH:16]([CH3:17])[CH3:18])=[O:32]