Phosphoric Acid → Tricalcium Phosphate
Reaction equation
[P:1](=[O:5])([OH:4])([OH:3])[OH:2].[O-2].[Ca+2:7]>O>[P:1]([O-:5])([O-:4])([O-:3])=[O:2].[Ca+2:7].[P:1]([O-:5])([O-:4])([O-:3])=[O:2].[Ca+2:7].[Ca+2:7]Participants
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Procedure
For example, according to pilot plant tests carried out by the Applicant, in order to produce 1 kg of a CMS-enriched calcium phosphate containing approximately 12% P and approximately 20% Ca, from phosphoric acid containing 57% P2O5, unslaked lime (90% CaO) containing 64,3% Ca and CMS, requires about 482 g (283 ml) H3PO4, about 311 g unslaked lime, about 405 g (311 ml) CMS and about 100 ml water. Similarly, to produce 1 kg of a CMS-enriched calcium phosphate containing approximately 16% P and approximately 18% Ca, requires about 645 g (379 ml) H3PO4, about 280 g unslaked lime, about 384 g (294 ml) CMS and about 100 ml water. Naturally, by varying the quantities of phosphoric acid, unslaked lime and CMS, a CMS-enriched calcium phosphate product having other relative proportions of P and Ca can be produced.
Sources & evidence
- ORD record
- ord-3a735e925ce7474b8db733b8e532037b
- Source dataset
- uspto-grants-1997_12
- Patent number
- US05693303
Reaction notes
Loading…