5-Methoxyindoleacetic acid → 5-Methoxytryptophol
Reaction equation
[CH3:1][O:2][C:3]1[CH:4]=[C:5]2[C:9](=[CH:10][CH:11]=1)[NH:8][CH:7]=[C:6]2[CH2:12][C:13](O)=[O:14].[H-].[Al+3].[Li+].[H-].[H-].[H-].S([O-])([O-])(=O)=O.[Mg+2]>O1CCCC1.C(OCC)C>[CH3:1][O:2][C:3]1[CH:4]=[C:5]2[C:9](=[CH:10][CH:11]=1)[NH:8][CH:7]=[C:6]2[CH2:12][CH2:13][OH:14]Participants
6
Procedure
A solution of 15 g of (5-methoxyindol-3-yl)acetic acid (0.073 mol) in 100 ml of tetrahydrofuran is added to a suspension of 2.1 g (0.219 mol) of lithium aluminum hydride in 100 ml of ethyl ether and the reaction mixture is brought to reflux for 6 hours. The reaction mixture is then hydrolyzed with 80 ml of a saturated aqueous magnesium sulfate solution. The whole mixture is filtered through celite and the solvents are evaporated under vacuum. The residue is taken up in a small amount of water and extracted a number of times with dichloromethane. The product is obtained after evaporation of the solvant.
Workup
- temperatureto reflux for 6 hours
- filtrationThe whole mixture is filtered through celite
- customthe solvents are evaporated under vacuum
- extractionextracted a number of times with dichloromethane
- customThe product is obtained
- customafter evaporation of the solvant
Sources & evidence
- ORD record
- ord-f4f4bc72d657402f9b183974ae18efa9
- Source dataset
- uspto-grants-1997_12
- Patent number
- US05703070
Reaction notes
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