Hydrochloric Acid → 2-Methyl-2-(4-nitrophenoxy)propanoic acid
Reaction equation
[N+:1]([C:4]1[CH:17]=[CH:16][C:7]([O:8][C:9]([CH3:15])([CH3:14])[C:10]([O:12]C)=[O:11])=[CH:6][CH:5]=1)([O-:3])=[O:2].[OH-].[Na+].Cl>CO.O>[N+:1]([C:4]1[CH:5]=[CH:6][C:7]([O:8][C:9]([CH3:15])([CH3:14])[C:10]([OH:12])=[O:11])=[CH:16][CH:17]=1)([O-:3])=[O:2]Participants
6
Reactant 3
Product 1
Reagents, catalysts & solvents 2
Procedure
Methyl 2-(4-nitrophenoxy)isobutyrate was dissolved in methanol (50 mL) and water (50 mL). Sodium hydroxide (5 g) was added. The solution was stirred at rt for 30 min, then acidified with 1N HCl aq. to pH ˜3. The aq. Solution was extracted with ethyl acetate (2×100 mL). The organic layers were evaporated to give 2-(4-nitrophenoxy)isobutyric acid.
Workup
- extractionThe aq. Solution was extracted with ethyl acetate (2×100 mL)
- customThe organic layers were evaporated
Sources & evidence
- ORD record
- ord-d197c686c78f4615855ab74c15d5c4b7
- Source dataset
- uspto-grants-2013_03
- Patent number
- US08399472B2
Reaction notes
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