HRID1954011

反应详情

EQUATION

反应方程式

HRID 1954011 的结构方程式

PROCEDURE

实验过程

Compound 18 (7.33 g, 8.99 mmol) was prepared from 16 (5.30 g, 9.99 mmol), 15 (4.13 g, 10.0 mmol), and NaHCO3 (2.52 g, 30.0 mmol) in 90% yield by the same method used for the preparation of 17. For 18: mp 138-140° C.; 1H NMR (DMSO-d6) d 1.50 (s, 9H, 3×CH3), 3.72, 3.83 (AB, Jgem =19 Hz, 2H, CH2S), 4.60 (s, 2H, OCH2CO), 4.99, 5.29 (AB, Jgem =15 Hz, 2H, CH2O), 5.18 (d, J=5.0 Hz, 1H, HC(6)), 5.79 (dd, J=5.0 and 9.5 Hz, 1H, HC(7)), 6.20 (br, 3H, 3×OH), 6.90-7.50 (m, 14H, 4×ArH), 8.30 (d, J=9.5 Hz, 1H, NH); IR (nujol): 3290-3370 (OH, NH), 1792 (β-lactam), 1750 (ester), 1730 (ester), 1688 (amide), 1620 (C=O) cm-1. Anal. (C41H35N2O12SCl) C, H, N, S, Cl.