反应详情

The general procedure from Example 1 was followed using PhCl (122 μl, 1.2 mmol) and p-toluidine (108 mg, 1.0 mmol) with Pd2 (dba)3 (20 mg, 0.0218 mmol) and (Me3C)2PH(O) (14.5 mg, 0.0878 mmol) and NaOtBu (144 mg, 1.5 mmol) in 3.0 mL of toluene. After 12 h, the reaction mixture was chromatographed with 5% ethyl acetate/hexane to give 80 mg (44% yield) of N-phenyl-p-toluidine. It was >95% pure by 1H NMR and GC/MS. 1H NMR (500 MHz, CDCl3): δ 7.13 (t, J=7.91 Hz, 2H), 6.98 (m, 2H), 6.89 (m, 4H), 6.78 (t, J=7.32 Hz, 1H), 5.46 (s, br. 1H), 2.20 (s, 3H) ppm. 13C NMR (125 MHz, CDCl3): d 143.9, 140.3, 130.8, 129.8, 129.2, 120.2, 118.9, 116.8, 20.6 ppm. MS: Calculated for C13H13N(M+): 183.3. Found: 184.1 (M+ +H).

1. customthe reaction mixture was chromatographed with 5% ethyl acetate/hexane