HRID1962439

反应详情

EQUATION

反应方程式

HRID 1962439 的结构方程式

PROCEDURE

实验过程

(S)-3-(tert-Butoxycarbonylamino)-1-(4-chloro-5-isoquinolinesulfonyl)-piperidine (Intermediate 18a) was prepared from 4-chloro-5-isoquinolinesulfonyl chloride (183 mg) and (S)-3-(tert-butoxycarbonylamino)piperidine (168 mg) according to the method described in Example 1-1, Step A, and then used in the method of Example 1-1, Step B in a similar manner to obtain the title compound as hydrochloride (164 mg).